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yyyymmdd Date.prototype.yyyymmdd = function() { var mm = this.getMonth() + 1; var dd = this.getDate(); return [this.getFullYear(), (mm>9 ? '' : '0') + mm, (dd>9 ? '' : '0') + dd ].join(''); }; var date = new Date(); date.yyyymmdd(); output "20180703" hhmmss Date.prototype.hhmmss = function() { var hh = this.getHours(); var mm = this.getMinutes(); var ss = this.getSeconds(); return [(hh>9 ? '' : ..

use POSIX 'strftime'; my $date = strftime '%Y%m%d', localtime; print $date; result $ perl test.pl 20171115관련글perl - n일 전 날짜 구하기references http://www.perlmonks.org/?node_id=673547